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#1134 - Armstrong Number
Problem Description
Given an integer n, return true if and only if it is an Armstrong number.
The k-digit number n is an Armstrong number if and only if the kth power of each digit sums to n.
Solution
/**
* @param {number} n
* @return {boolean}
*/
var isArmstrong = function(n) {
const digits = n.toString();
const digitCount = digits.length;
const digitSum = digits
.split('')
.reduce((sum, digit) => sum + Math.pow(parseInt(digit, 10), digitCount), 0);
return digitSum === n;
};