#2840 - Check if Strings Can be Made Equal With Operations II

Medium • View on LeetCode • View on GitHub

Problem Description

You are given two strings s1 and s2, both of length n, consisting of lowercase English letters.

You can apply the following operation on any of the two strings any number of times:

Choose any two indices i and j such that i < j and the difference j - i is even, then swap the two characters at those indices in the string.

Return true if you can make the strings s1 and s2 equal, and false otherwise.

Solution

/**
 * @param {string} s1
 * @param {string} s2
 * @return {boolean}
 */
var checkStrings = function(s1, s2) {
  const evenChars1 = [];
  const oddChars1 = [];
  const evenChars2 = [];
  const oddChars2 = [];

  for (let i = 0; i < s1.length; i++) {
    if (i % 2 === 0) {
      evenChars1.push(s1[i]);
      evenChars2.push(s2[i]);
    } else {
      oddChars1.push(s1[i]);
      oddChars2.push(s2[i]);
    }
  }

  return evenChars1.sort().join('') === evenChars2.sort().join('')
    && oddChars1.sort().join('') === oddChars2.sort().join('');
};