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#40 - Combination Sum II
Problem Description
Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sum to target.
Each number in candidates may only be used once in the combination.
Note: The solution set must not contain duplicate combinations.
Solution
/**
* @param {number[]} candidates
* @param {number} target
* @return {number[][]}
*/
var combinationSum2 = function(candidates, target) {
const result = [];
candidates.sort((a, b) => a - b);
backtrack(result, candidates, target);
return result;
};
function backtrack(result, candidates, target, combination = [], offset = 0) {
if (target < 0) {
return;
} else if (target === 0) {
result.push(combination);
} else {
for (let i = offset; i < candidates.length; i++) {
if (i > offset && candidates[i] === candidates[i - 1]) continue;
backtrack(result, candidates, target - candidates[i], [...combination, candidates[i]], i + 1);
}
}
}