#3169 - Count Days Without Meetings

Medium • View on LeetCode • View on GitHub

Problem Description

You are given a positive integer days representing the total number of days an employee is available for work (starting from day 1). You are also given a 2D array meetings of size n where, meetings[i] = [start_i, end_i] represents the starting and ending days of meeting i (inclusive).

Return the count of days when the employee is available for work but no meetings are scheduled.

Note: The meetings may overlap.

Solution

/**
 * @param {number} days
 * @param {number[][]} meetings
 * @return {number}
 */
var countDays = function(days, meetings) {
  meetings.sort((a, b) => a[0] - b[0]);

  let result = 0;
  let currentEnd = 0;

  for (const [start, end] of meetings) {
    if (start > currentEnd + 1) {
      result += start - currentEnd - 1;
    }
    currentEnd = Math.max(currentEnd, end);
  }

  if (currentEnd < days) {
    result += days - currentEnd;
  }

  return result;
};