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#2221 - Find Triangular Sum of an Array
Problem Description
You are given a 0-indexed integer array nums, where nums[i] is a digit between 0 and 9 (inclusive).
The triangular sum of nums is the value of the only element present in nums after the following process terminates:
- Let nums comprise of n elements. If n == 1, end the process. Otherwise, create a new 0-indexed integer array newNums of length n - 1.
- For each index i, where 0 <= i < n - 1, assign the value of newNums[i] as (nums[i] + nums[i+1]) % 10, where % denotes modulo operator.
- Replace the array nums with newNums.
- Repeat the entire process starting from step 1.
Return the triangular sum of nums.
Solution
/**
* @param {number[]} nums
* @return {number}
*/
var triangularSum = function(nums) {
while (nums.length > 1) {
const updated = [];
for (let i = 0; i < nums.length - 1; i++) {
updated.push((nums[i] + nums[i + 1]) % 10);
}
nums = updated;
}
return nums[0];
};