#2873 - Maximum Value of an Ordered Triplet I

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Problem Description

You are given a 0-indexed integer array nums.

Return the maximum value over all triplets of indices (i, j, k) such that i < j < k.

If all such triplets have a negative value, return 0.

The value of a triplet of indices (i, j, k) is equal to (nums[i] - nums[j]) * nums[k].

Solution

/**
 * @param {number[]} nums
 * @return {number}
 */
var maximumTripletValue = function(nums) {
  let result = 0;

  for (let i = 0; i < nums.length - 2; i++) {
    for (let j = i + 1; j < nums.length - 1; j++) {
      const diff = nums[i] - nums[j];
      if (diff <= 0) continue;
      for (let k = j + 1; k < nums.length; k++) {
        result = Math.max(result, diff * nums[k]);
      }
    }
  }

  return result;
};