#1480 - Running Sum of 1d Array

Easy • View on LeetCode • View on GitHub

Problem Description

Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.

Solution

/**
 * @param {number[]} nums
 * @return {number[]}
 */
var runningSum = function(nums) {
  for (let i = 1; i < nums.length; i++) {
    nums[i] = nums[i - 1] + nums[i];
  }
  return nums;
};